-16x^2+156x+150=0

Solution for -16x^2+156x+150=0 equation:

-16x^2+156x+150=0

a = -16; b = 156; c = +150;
Δ = b2-4ac
Δ = 1562-4·(-16)·150
Δ = 33936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{33936}=\sqrt{16*2121}=\sqrt{16}*\sqrt{2121}=4\sqrt{2121}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(156)-4\sqrt{2121}}{2*-16}=\frac{-156-4\sqrt{2121}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(156)+4\sqrt{2121}}{2*-16}=\frac{-156+4\sqrt{2121}}{-32}
$